Function: PVInt - numerical principal value integral

Calling sequence:
PVint(f, x=a..b, p)


f - the integrand, expression in one variable x

x - name

a, b - real constants, the endpoints of the integration

p - real constant, location of a singularity in the interval of integration



> PVInt(tan(x), x = 0 .. 2, Pi/2);


This one could have been integrated symbolically.

> int(tan(x),x=0..2,CauchyPrincipalValue);


> evalf(%);


The singularity at x = Pi/2 would cause ordinary numerical integration to fail.

> evalf(Int(tan(x),x=0..2));

Error, (in evalf/int) numeric exception: invalid operation

The next one can not be integrated symbolically: presumably there is no closed form for the integral.

> int(1/(x+sin(x)),x);


> PVInt(1/(x+sin(x)),x=-1..2,0);


The next one diverges.

> PVInt(1/(sin(x)^3+x^4), x=-1..2, 0);


The location of the singularity must be known exactly. A floating-point approximation would not be enough.

> p0:= fsolve(exp(x)-3*x,x=0..1);

p0 := .6190612867

> PVInt(1/(exp(x)-3*x),x=0..1,p0);

Error, (in evalf/int) unable to handle singularity

Since it depends on finding a finite number of terms with negative exponents in the Laurent series, PVInt will not work with singularities that are essential or non-isolated. For example, the following principal value integral is 0 by symmetry, but PVInt can't evaluate it.

> PVInt(exp(1/x)-exp(-1/x),x=-1..1,0);

Error, (in numapprox[laurent]) unable to compute Laurent series

See also:

int , int[numeric]

Maple Advisor Database R. Israel, 2000