2(d)

The equation is separable.

\begin{displaymath}\int \frac{y+1}{y} \, dy = \int \frac{x+1}{x} \, dx \end{displaymath}

so $ y + \ln \vert y\vert = x + \ln \vert x\vert + C $. There is no way to solve this explicitly for y, although you might take the exponential of both sides to get $\displaystyle y {\rm e}^y = A x {\rm e}^x $.




Robert Israel
2002-02-07