If we know the distance (r) from the center of the tetrahedron to one of its vertices, the lengths (a) of the edges is given by a = (2√6) / 3,
then the area of one triangle is (a × h) / 2, where h = √[a² - (a/2)²].
And the area of the tetrahedron is 4 × the area of one triangle.
|The volume of a tetrahedron in terms of its edge length: V = a³(√2 / 12)
In a more general case, i.e. any tetra hedron with vertices a, b, c, d.
To calculate the volume, first we treat all edges like vectors. Then,